ps. look out for all my other solutions for Advent of Code challenges here.
See details of the challenge here.
First, let’s capture the input for today’s challenge in a text file, say Day03Input.txt.
Then, let’s create a module to capture the common steps between both parts of the challenge.
There’s really not much to be said about the code snippet above, and the solution for part 1 is also really simple.
Now that you’ve helpfully marked up their design documents, it occurs to you
that triangles are specified in groups of three vertically. Each set of three
numbers in a column specifies a triangle. Rows are unrelated.
For example, given the following specification, numbers with the same hundreds
digit would be part of the same triangle:
101 301 501
102 302 502
103 303 503
201 401 601
202 402 602
203 403 603
In your puzzle input, and instead reading by columns, how many of the listed
triangles are possible?
You could, transpose the input (ie, a int) so that you end up with something along the lines of:
101 102 103 201 202 203 …
301 302 303 401 402 403 …
501 502 503 601 602 603 …
which will be easier to process, but it feels like more work than I’d like to do.
An alternative approach – the one I went with – is to use Seq.chunkBySize to group row indices into chunks of 3. For each chunk you can flat map (in F#, that’s Seq.collect) it to 3 triangles.
After that, it’s a case of applying the isFilter function we declared earlier on the resulting sequence.
- Day 3 challenge description
- Advent of Code 2015
- Solution for Day 2
- All my F# solutions for Advent of Code
- Github repo
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