Project Euler – Problem 76 Solution

Problem

It is possible to write five as a sum in exactly six different ways:

4 + 1

3 + 2

3 + 1 + 1

2 + 2 + 1

2 + 1 + 1 + 1

1 + 1 + 1 + 1 + 1

How many different ways can one hundred be written as a sum of at least two positive integers?

Solution

// implement the coin change algorithm
let rec count n m (coins:int list) =
    if n = 0 then 1
    else if n < 0 then 0
    else if (m <= 0 && n >= 1) then 0
    else (count n (m-1) coins) + (count (n-coins.[m-1]) m coins)

let answer = count 100 99 [1..99]

This is basically problem 31 with a twist, using the same coin change algorithm but substitute the set coins with the numbers less than 100 and you’ll have your solution!

Subscribe to my newsletter and get new contents delivered straight to your inbox :-)