Problem
Take the number 192 and multiply it by each of 1, 2, and 3:
192 x 1 = 192
192 x 2 = 384
192 x 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)
The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, … , n) where n > 1?
Solution
// define function which checks if a given number is 1-9 pandigital
let isPandigital n =
let str = n.ToString()
[1..9]
|> List.map string
|> List.forall (fun x -> str.Contains(x) && str.IndexOf(x) = str.LastIndexOf(x))
// define function to generate the (possible) pandigital sequence
let getConcatProduct n =
// define recursive inner function
let rec genSeq n' (digits:string) n=
let digits' = digits + (n' * n).ToString()
if digits'.Length > 9 then digits else genSeq (n'+1) digits' n
genSeq 1 "" n
let answer =
[1..10000]
|> List.map getConcatProduct
|> List.filter (fun d -> d.Length = 9 && isPandigital d)
|> List.maxBy int
Seeing as n must be greater than 1 as specified in the problem brief, we only needs to check numbers up to 10000 as the concatenated form of two 5-digit numbers will be longer than 9 digits.
The getConcatProduct function does most of the interesting work and is responsible for taking a number and returning the concatenated product of that number and 1, 2.. up to 9. The last section of the code checks the outputs and only look for concatenated products that are 9 digits long and pandigital from 1 to 9, finding the largest number of this kind.
