Yan Cui
I help clients go faster for less using serverless technologies.
Problem
The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 – 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
Solution
let numbers = [|1..100|] let sumOfSquares = numbers |> Array.map (fun x -> x * x) |> Array.sum let sum = numbers |> Array.sum let squareOfSum = sum * sum let diff = squareOfSum – sumOfSquares
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here’s without defining any functions, but same approach.
(List.sum [1..100] |> (fun x -> x*x)) – (List.map (fun x -> x*x)[1..100] |> List.sum)