Yan Cui

I help clients go faster for less using serverless technologies.

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#### Problem

By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23.

That is, 3 + 7 + 4 + 9 = 23.

Find the maximum total from top to bottom intriangle.txt(right click and ‘Save Link/Target As…’), a 15K text file containing a triangle with one-hundred rows.

NOTE:This is a much more difficult version ofProblem 18. It is not possible to try every route to solve this problem, as there are 2^{99}altogether! If you could check one trillion (10^{12}) routes every second it would take over twenty billion years to check them all. There is an efficient algorithm to solve it. ;o)

#### Solution

open System.IO

// covers the data in the text to a triangle of ints, i.e. int list list

let triangle =

File.ReadAllLines(@”C:\TEMP\triangle.txt”)

|> Array.map (fun s -> s.Split(‘ ‘) |> Array.map int32 |> Array.toList)

|> Array.toList

// function to return all the combinations of n elements from the supplied list

let rec comb n list =

match n, list with

| 0, _ -> [[]]

| _, [] -> []

| k, (x::xs) -> List.map ((@) [x]) (comb (k-1) xs) @ (comb k xs)

// calculates the next row in the T triangle given the new row in R and the last row in T

let getNewTotal (row:int list) (total:int list) =

let head = total.Head

let tail = List.nth total (total.Length-1)

let body = total |> Seq.windowed 2 |> Seq.map (fun l -> Seq.max l) |> Seq.toList

List.map2 (+) row (List.concat [[head]; body; [tail]])

// recursively traverse down the R triangle and return the last row in T

let rec traverse (raw:int list list) (total:int list) n =

let row = raw.[n]

let newTotal = getNewTotal row total

if n < (raw.Length-1) then traverse raw newTotal (n+1) else newTotal let answer = List.max (traverse triangle [59] 1) [/code] See problem 18 solution for the full explanation of this solution.

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